"Relationship between Homogeneous Equilibrium and the Law of Mass Action (Part B)"
Case
B- In gaseous reaction when no of moles increases:
Suppose the decomposition of PCl5
PCl5
à PCl3
+ Cl2
t=0 a 0
0
t=eq (a-x) x x
Total no of moles “N” are (a-x) + x + x = a
Expression
for Kc:
[PCl5] = (a-x)/V
[PCl3] = x/V
[Cl2] = x/V
Kc
= [PCl3][
Cl2]
[PCl5]
Kc = [x/V] [x/V]
(a-x)/V
Kc = x2
(a-x)V
Reaction will move towards forwards direction when there
is increase in volume that
decreases Kc
to make Kc constant.
Expression for Kp:
PPCl5
= (a-x) P
(a+x)
PCl2
= (x)
P
(a+x)
P
PCl5 = (x) P
(a+x)
Put
the values in Kp expression
Kp
= PPCl3
PCl2
PPCl5
(x) P . (x)
P
Kp = (a+b) (a+b) = x2 P
(a-x)
P (a2-x2)
(a+x)
Reaction will move towards backward direction when there
is increase in pressure that
increases Kp to make Kp constant.
Expression for Kx:
XPCl5
= (a-x)
(a+x)
XCl2
= (x)
(a+x)
X
PCl5 = (x)
(a+x)
Put
the values in Kx expression
Kx
= XPCl3
XCl2 *
XPCl5
(x)
. (x)
Kx
= (a+b) (a+b) = x2
(a-x) (a2-x2)
(a+x)
This
equation highlights that the rate of reaction at equilibrium is proportional to
the concentrations of reactants, as per the Law of Mass Action.
Conclusion:
Homogeneous and heterogeneous
equilibrium are distinct types of chemical equilibrium, each with its own
characteristics and application of equilibrium constants, be it Kc
or Kp. The Law of Mass Action is a universal principle that governs
both types, emphasizing the significance of reactant concentrations in reaching
a state of equilibrium. Understanding these concepts is fundamental to grasping
the intricacies of chemical equilibrium and its role in the behavior of chemical
reactions. Whether dealing with gases, liquids, or solids, these principles and
equilibrium constants play a central role in the world of chemistry.
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